34 lines
1.5 KiB
COBOL
34 lines
1.5 KiB
COBOL
*> Code altered from https://www.quora.com/What-is-a-COBOL-program-that-will-solve-a-quadratic-equation
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*> Program finds the roots to a simple quadratic equation
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IDENTIFICATION DIVISION.
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PROGRAM-ID. QuadraticSolver.
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DATA DIVISION.
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WORKING-STORAGE SECTION.
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77 a PIC S9(5)V9(5) COMP-3 VALUE 1.
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77 b PIC S9(5)V9(5) COMP-3 VALUE 5.
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77 c PIC S9(5)V9(5) COMP-3 VALUE 6.
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77 discriminant PIC S9(5)V9(5) COMP-3.
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77 root1 PIC S9(5)V9(5) COMP-3.
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77 root2 PIC S9(5)V9(5) COMP-3.
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77 square-root-discriminant PIC S9(5)V9(5) COMP-3.
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PROCEDURE DIVISION. *> program begins here
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DISPLAY "EQUATION: (1x^2) + 5x + 6 = 0"
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COMPUTE discriminant = (b ** 2) - (4 * a * c)
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IF discriminant > 0
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COMPUTE square-root-discriminant = FUNCTION SQRT(discriminant)
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COMPUTE root1 = (-b + square-root-discriminant) / (2 * a)
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COMPUTE root2 = (-b - square-root-discriminant) / (2 * a)
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DISPLAY "The equation has two distinct real roots: "
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DISPLAY "Root 1: " root1
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DISPLAY "Root 2: " root2
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ELSE IF discriminant = 0
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COMPUTE root1 = -b / (2 * a)
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DISPLAY "The equation has one real root: "
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DISPLAY "Root: " root1
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ELSE
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DISPLAY "The equation has no real roots."
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END-IF
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STOP RUN.
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