*> Code altered from https://www.quora.com/What-is-a-COBOL-program-that-will-solve-a-quadratic-equation
       *> Program finds the roots to a simple quadratic equation

       IDENTIFICATION DIVISION.
       PROGRAM-ID. QuadraticSolver.
       DATA DIVISION.
           WORKING-STORAGE SECTION.
           77 a PIC S9(5)V9(5) COMP-3 VALUE 1.
           77 b PIC S9(5)V9(5) COMP-3 VALUE 5.
           77 c PIC S9(5)V9(5) COMP-3 VALUE 6.
           77 discriminant PIC S9(5)V9(5) COMP-3.
           77 root1 PIC S9(5)V9(5) COMP-3.
           77 root2 PIC S9(5)V9(5) COMP-3.
           77 square-root-discriminant PIC S9(5)V9(5) COMP-3.

       PROCEDURE DIVISION. *> program begins here
           DISPLAY "EQUATION: (1x^2) + 5x + 6 = 0" 
           COMPUTE discriminant = (b ** 2) - (4 * a * c)

           IF discriminant > 0
               COMPUTE square-root-discriminant = FUNCTION SQRT(discriminant)
               COMPUTE root1 = (-b + square-root-discriminant) / (2 * a)
               COMPUTE root2 = (-b - square-root-discriminant) / (2 * a)
               DISPLAY "The equation has two distinct real roots: "
               DISPLAY "Root 1: " root1
               DISPLAY "Root 2: " root2
           ELSE IF discriminant = 0
               COMPUTE root1 = -b / (2 * a)
               DISPLAY "The equation has one real root: "
               DISPLAY "Root: " root1
           ELSE
               DISPLAY "The equation has no real roots."
           END-IF
       STOP RUN.