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Jenessy Lustre 2024-10-15 10:47:00 -07:00
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# Language Proposal # Language Proposal
TODO Detail language here ### 1. Hello World
### 2. Quadratic Function
- Note: code needs to be formatted
- credit to [Marco Biagini](https://www.quora.com/What-is-a-COBOL-program-that-will-solve-a-quadratic-equation)
- a quadratic equation of the form **ax^2 + bx + c = 0**
#### Input
User will be prompted for a, b, and c (ex. 1, 5, 6)
#### Output
Program will display the real roots or if there are no real roots (ex. -2, -3)
### 3. Integer Sort
### 4. Language Features

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/*code from https://www.quora.com/What-is-a-COBOL-program-that-will-solve-a-quadratic-equation
IDENTIFICATION DIVISION.
PROGRAM-ID. QuadraticSolver.
DATA DIVISION.
WORKING-STORAGE SECTION.
77 a PIC S9(5)V9(5) COMP-3.
77 b PIC S9(5)V9(5) COMP-3.
77 c PIC S9(5)V9(5) COMP-3.
77 discriminant PIC S9(5)V9(5) COMP-3.
77 root1 PIC S9(5)V9(5) COMP-3.
77 root2 PIC S9(5)V9(5) COMP-3.
77 square-root-discriminant PIC S9(5)V9(5) COMP-3.
PROCEDURE DIVISION.
DISPLAY "Enter the coefficients of the quadratic equation (a, b, c): ".
ACCEPT a
ACCEPT b
ACCEPT c
COMPUTE discriminant = (b ** 2) - (4 * a * c)
IF discriminant > 0
COMPUTE square-root-discriminant = FUNCTION SQRT(discriminant)
COMPUTE root1 = (-b + square-root-discriminant) / (2 * a)
COMPUTE root2 = (-b - square-root-discriminant) / (2 * a)
DISPLAY "The equation has two distinct real roots: "
DISPLAY "Root 1: " root1
DISPLAY "Root 2: " root2
ELSE IF discriminant = 0
COMPUTE root1 = -b / (2 * a)
DISPLAY "The equation has one real root: "
DISPLAY "Root: " root1
ELSE
DISPLAY "The equation has no real roots."
STOP RUN.